Integrand size = 29, antiderivative size = 143 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=\frac {a A \sin (c+d x)}{d}+\frac {(A b+a B) \sin ^2(c+d x)}{2 d}-\frac {(2 a A-b B) \sin ^3(c+d x)}{3 d}-\frac {(A b+a B) \sin ^4(c+d x)}{2 d}+\frac {(a A-2 b B) \sin ^5(c+d x)}{5 d}+\frac {(A b+a B) \sin ^6(c+d x)}{6 d}+\frac {b B \sin ^7(c+d x)}{7 d} \]
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Time = 0.11 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {2916, 786} \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=\frac {(a B+A b) \sin ^6(c+d x)}{6 d}+\frac {(a A-2 b B) \sin ^5(c+d x)}{5 d}-\frac {(a B+A b) \sin ^4(c+d x)}{2 d}-\frac {(2 a A-b B) \sin ^3(c+d x)}{3 d}+\frac {(a B+A b) \sin ^2(c+d x)}{2 d}+\frac {a A \sin (c+d x)}{d}+\frac {b B \sin ^7(c+d x)}{7 d} \]
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Rule 786
Rule 2916
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int (a+x) \left (A+\frac {B x}{b}\right ) \left (b^2-x^2\right )^2 \, dx,x,b \sin (c+d x)\right )}{b^5 d} \\ & = \frac {\text {Subst}\left (\int \left (a A b^4+b^3 (A b+a B) x+b^2 (-2 a A+b B) x^2-2 b (A b+a B) x^3+(a A-2 b B) x^4+\frac {(A b+a B) x^5}{b}+\frac {B x^6}{b}\right ) \, dx,x,b \sin (c+d x)\right )}{b^5 d} \\ & = \frac {a A \sin (c+d x)}{d}+\frac {(A b+a B) \sin ^2(c+d x)}{2 d}-\frac {(2 a A-b B) \sin ^3(c+d x)}{3 d}-\frac {(A b+a B) \sin ^4(c+d x)}{2 d}+\frac {(a A-2 b B) \sin ^5(c+d x)}{5 d}+\frac {(A b+a B) \sin ^6(c+d x)}{6 d}+\frac {b B \sin ^7(c+d x)}{7 d} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.81 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=\frac {\sin (c+d x) \left (210 a A+105 (A b+a B) \sin (c+d x)-70 (2 a A-b B) \sin ^2(c+d x)-105 (A b+a B) \sin ^3(c+d x)+42 (a A-2 b B) \sin ^4(c+d x)+35 (A b+a B) \sin ^5(c+d x)+30 b B \sin ^6(c+d x)\right )}{210 d} \]
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Time = 0.84 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.81
method | result | size |
derivativedivides | \(\frac {\frac {B b \left (\sin ^{7}\left (d x +c \right )\right )}{7}+\frac {\left (A b +B a \right ) \left (\sin ^{6}\left (d x +c \right )\right )}{6}+\frac {\left (a A -2 B b \right ) \left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (-2 A b -2 B a \right ) \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (-2 a A +B b \right ) \left (\sin ^{3}\left (d x +c \right )\right )}{3}+\frac {\left (A b +B a \right ) \left (\sin ^{2}\left (d x +c \right )\right )}{2}+A \sin \left (d x +c \right ) a}{d}\) | \(116\) |
default | \(\frac {\frac {B b \left (\sin ^{7}\left (d x +c \right )\right )}{7}+\frac {\left (A b +B a \right ) \left (\sin ^{6}\left (d x +c \right )\right )}{6}+\frac {\left (a A -2 B b \right ) \left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (-2 A b -2 B a \right ) \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (-2 a A +B b \right ) \left (\sin ^{3}\left (d x +c \right )\right )}{3}+\frac {\left (A b +B a \right ) \left (\sin ^{2}\left (d x +c \right )\right )}{2}+A \sin \left (d x +c \right ) a}{d}\) | \(116\) |
parallelrisch | \(\frac {-210 A \cos \left (4 d x +4 c \right ) b -525 A \cos \left (2 d x +2 c \right ) b +4200 A \sin \left (d x +c \right ) a -35 A \cos \left (6 d x +6 c \right ) b +84 A \sin \left (5 d x +5 c \right ) a +700 a A \sin \left (3 d x +3 c \right )-210 B \cos \left (4 d x +4 c \right ) a -525 B \cos \left (2 d x +2 c \right ) a +525 B b \sin \left (d x +c \right )-15 B \sin \left (7 d x +7 c \right ) b -35 B \cos \left (6 d x +6 c \right ) a -63 B \sin \left (5 d x +5 c \right ) b -35 B \sin \left (3 d x +3 c \right ) b +770 A b +770 B a}{6720 d}\) | \(178\) |
risch | \(\frac {5 a A \sin \left (d x +c \right )}{8 d}+\frac {5 b B \sin \left (d x +c \right )}{64 d}-\frac {\sin \left (7 d x +7 c \right ) B b}{448 d}-\frac {\cos \left (6 d x +6 c \right ) A b}{192 d}-\frac {\cos \left (6 d x +6 c \right ) B a}{192 d}+\frac {\sin \left (5 d x +5 c \right ) a A}{80 d}-\frac {3 \sin \left (5 d x +5 c \right ) B b}{320 d}-\frac {\cos \left (4 d x +4 c \right ) A b}{32 d}-\frac {\cos \left (4 d x +4 c \right ) B a}{32 d}+\frac {5 a A \sin \left (3 d x +3 c \right )}{48 d}-\frac {\sin \left (3 d x +3 c \right ) B b}{192 d}-\frac {5 \cos \left (2 d x +2 c \right ) A b}{64 d}-\frac {5 \cos \left (2 d x +2 c \right ) B a}{64 d}\) | \(204\) |
norman | \(\frac {\frac {\left (2 A b +2 B a \right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {\left (2 A b +2 B a \right ) \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {\left (2 A b +2 B a \right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {\left (2 A b +2 B a \right ) \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {4 \left (5 a A +2 B b \right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {4 \left (5 a A +2 B b \right ) \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {8 \left (91 a A +38 B b \right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{35 d}+\frac {2 \left (113 a A -16 B b \right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d}+\frac {2 \left (113 a A -16 B b \right ) \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d}+\frac {5 \left (4 A b +4 B a \right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {5 \left (4 A b +4 B a \right ) \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {2 a A \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}+\frac {2 a A \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{7}}\) | \(323\) |
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Time = 0.26 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.62 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=-\frac {35 \, {\left (B a + A b\right )} \cos \left (d x + c\right )^{6} + 2 \, {\left (15 \, B b \cos \left (d x + c\right )^{6} - 3 \, {\left (7 \, A a + B b\right )} \cos \left (d x + c\right )^{4} - 4 \, {\left (7 \, A a + B b\right )} \cos \left (d x + c\right )^{2} - 56 \, A a - 8 \, B b\right )} \sin \left (d x + c\right )}{210 \, d} \]
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Time = 0.46 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.24 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=\begin {cases} \frac {8 A a \sin ^{5}{\left (c + d x \right )}}{15 d} + \frac {4 A a \sin ^{3}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{3 d} + \frac {A a \sin {\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{d} - \frac {A b \cos ^{6}{\left (c + d x \right )}}{6 d} - \frac {B a \cos ^{6}{\left (c + d x \right )}}{6 d} + \frac {8 B b \sin ^{7}{\left (c + d x \right )}}{105 d} + \frac {4 B b \sin ^{5}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{15 d} + \frac {B b \sin ^{3}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{3 d} & \text {for}\: d \neq 0 \\x \left (A + B \sin {\left (c \right )}\right ) \left (a + b \sin {\left (c \right )}\right ) \cos ^{5}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.81 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=\frac {30 \, B b \sin \left (d x + c\right )^{7} + 35 \, {\left (B a + A b\right )} \sin \left (d x + c\right )^{6} + 42 \, {\left (A a - 2 \, B b\right )} \sin \left (d x + c\right )^{5} - 105 \, {\left (B a + A b\right )} \sin \left (d x + c\right )^{4} - 70 \, {\left (2 \, A a - B b\right )} \sin \left (d x + c\right )^{3} + 210 \, A a \sin \left (d x + c\right ) + 105 \, {\left (B a + A b\right )} \sin \left (d x + c\right )^{2}}{210 \, d} \]
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Time = 0.39 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.01 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=-\frac {B b \sin \left (7 \, d x + 7 \, c\right )}{448 \, d} - \frac {{\left (B a + A b\right )} \cos \left (6 \, d x + 6 \, c\right )}{192 \, d} - \frac {{\left (B a + A b\right )} \cos \left (4 \, d x + 4 \, c\right )}{32 \, d} - \frac {5 \, {\left (B a + A b\right )} \cos \left (2 \, d x + 2 \, c\right )}{64 \, d} + \frac {{\left (4 \, A a - 3 \, B b\right )} \sin \left (5 \, d x + 5 \, c\right )}{320 \, d} + \frac {{\left (20 \, A a - B b\right )} \sin \left (3 \, d x + 3 \, c\right )}{192 \, d} + \frac {5 \, {\left (8 \, A a + B b\right )} \sin \left (d x + c\right )}{64 \, d} \]
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Time = 12.50 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.83 \[ \int \cos ^5(c+d x) (a+b \sin (c+d x)) (A+B \sin (c+d x)) \, dx=\frac {\frac {B\,b\,{\sin \left (c+d\,x\right )}^7}{7}+\left (\frac {A\,b}{6}+\frac {B\,a}{6}\right )\,{\sin \left (c+d\,x\right )}^6+\left (\frac {A\,a}{5}-\frac {2\,B\,b}{5}\right )\,{\sin \left (c+d\,x\right )}^5+\left (-\frac {A\,b}{2}-\frac {B\,a}{2}\right )\,{\sin \left (c+d\,x\right )}^4+\left (\frac {B\,b}{3}-\frac {2\,A\,a}{3}\right )\,{\sin \left (c+d\,x\right )}^3+\left (\frac {A\,b}{2}+\frac {B\,a}{2}\right )\,{\sin \left (c+d\,x\right )}^2+A\,a\,\sin \left (c+d\,x\right )}{d} \]
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